Arithmetic operator  | Java

Arithmetic operator | Java

Basics • Java Fundamentals

Arithmetic operators in Java are used to perform mathematical operations on numerical values. These operations include addition, subtraction, multiplication, division, and modulo (remainder). Here's an explanation of each arithmetic operator:

  1. Addition +:

    • Adds two operands.

    • Example: int sum = 5 + 3; // sum is 8

  2. Subtraction -:

    • Subtracts the right operand from the left operand.

    • Example: int difference = 7 - 4; // difference is 3

  3. Multiplication *:

    • Multiplies two operands.

    • Example: int product = 2 * 6; // product is 12

  4. Division /:

    • Divides the left operand by the right operand.

    • Example: int quotient = 10 / 2; // quotient is 5

  5. Modulo %:

    • Returns the remainder of the division of the left operand by the right operand.

    • Example: int remainder = 10 % 3; // remainder is 1

Here's a more comprehensive example that demonstrates the use of various arithmetic operators:

public class ArithmeticExample {
    public static void main(String[] args) {
        int a = 10;
        int b = 4;

        int sum = a + b;         // 14
        int difference = a - b;  // 6
        int product = a * b;     // 40
        int quotient = a / b;    // 2
        int remainder = a % b;   // 2

        System.out.println("Sum: " + sum);
        System.out.println("Difference: " + difference);
        System.out.println("Product: " + product);
        System.out.println("Quotient: " + quotient);
        System.out.println("Remainder: " + remainder);
    }
}

In this example, the variables a and b are used to demonstrate the various arithmetic operations, and the results are printed to the console. Keep in mind that integer division in Java truncates the fractional part, so the result of a / b is an integer. If you need a floating-point result, you can use double or float variables.

  • If we apply any arithmetic operator between two variables a and b the result type will be always -
    max(type a, type b)

  • According to flowchart -

Data Type aData Type bResulting Data Type
bytebyteint
byteshortint
shortbyteint
charcharint
charintint
bytelonglong
longdoubledouble
chardoubledouble
  • Data type have same size less than int or equal to int will always result int.

  • Data type have size more than the highest values will be considered.

Example -

public class ArithmeticExample {
    public static void main(String[] args) {
        System.out.println('a' + 'b'); //195
        System.out.println('a' + 0.89); // 97.89
    }
}

Infinity

  • It results in numbers divided by zero.

  • In Integral arithmetic that is (byte, short, int, long) there is no way to represent infinity. Hence, if Infinity is result we will get arithmetic exception i.e., ArithmeticException: / by zero

public class ArithmeticExample {
    public static void main(String[] args) {
        System.out.println(5 / 0); // ArithmeticException: / by zero
    }
}
  • In floating point arithmetic (float and double) there is always a way to represent infinity.

  • For this float and double classes contains the following constants that is -
    POSITIVE_INFINITY NEGATIVE_INFINITY

  • Health even though result is Infinity and we wouldn't get any arithmetic exception in floating point arithmetic.

public class Test {
    public static void main(String[] args) {
        System.out.println(10.0 / 0); // Infinity
        System.out.println(-5 / 0.0); // -Infinity

    }
}

Not a Number (NaN)

  • It results when we divide zero by zero.

  • An integral arithmetic there is no way to undefine the result.

  • If the result is undefined we will get arithmetic exception i.e., ArithmeticException: / by zero

public class ArithmeticExample {
    public static void main(String[] args) {
        System.out.println(0 / 0); // ArithmeticException: / by zero
    }
}
  • But in floating point arithmetic there is a way to represent undefined result.

  • For this flute and double classes contain NaN constant hence if the result is undefined we won't get any runtime exception in floating point arithmetic.

public class ArithmeticExample {
    public static void main(String[] args) {
        System.out.println(0.0 / 0); // NaN
        System.out.println(-0.0 / 0); // NaN
    }
}

Note:

  • For any X value including NaN the following expression returns false -

    x < NaN, x > NaN, x <= NaN, x >= NaN and x == NaN.

  • For any X value including NaN the following expression returns true -

    x != NaN.

public class Test {
    public static void main(String[] args) {
        System.out.println(10 < Float.NaN);        // false
        System.out.println(10 > Float.NaN);        // false
        System.out.println(10 <= Float.NaN);       // false
        System.out.println(10 >= Float.NaN);       // false
        System.out.println(10 == Float.NaN);       // false
        System.out.println(Float.NaN == Float.NaN);// false
        System.out.println(10 != Float.NaN);       // true
        System.out.println(Float.NaN == Float.NaN);// false
    }
}

Arithmetic exception

  • it is runtime exception not compile time error

  • It only occurred integral arithmetic but not in floating point.

  • The only operator which cause arithmetic exception are / and %

String concatenation operator (+)

  • The only overrated operator in Java is + operator.

  • sometime it act as arithmetic addition operator and some time it acts as a string concatenation operator.

  • If at least one argument is a string type then + operator act as Concatenation Operator and if both arguments are number type then + operator act as arithmetic addition operator.

public class Test {
    public static void main(String[] args) {
        String s = "Hello";
        int a = 10, b = 20, c = 30;
        System.out.println(s + a + b + c); // Hello102030
        System.out.println(a + s + b + c); // 10Hello2030
        System.out.println(a + b + s + c); // 30Hello30
        System.out.println(a + b + c + s); // 60Hello
    }
}

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